What is 1/2 (ln(e^2+1)-ln(2)) ?

The solution to 1/2 (ln(e^2+1)-ln(2)) is 1/2 ln((e^2+1)/2)

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simplify 1/2 (ln(e^2+1)-ln(2))

simplify

\frac{1}{2} (ln (e^{2} + 1) - ln (2))

\frac{1}{2} ln (\frac{e ^{2} + 1}{2})

Decimal Notation

0.71689 \dots

Solution steps

\frac{1}{2} (ln (e^{2} + 1) - ln (2))

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (e^{2} + 1) - ln (2) = ln (\frac{e ^{2} + 1}{2})

= \frac{1}{2} ln (\frac{e ^{2} + 1}{2})

lo g_{6} (\frac{6}{x})

- 100 ln (\frac{1}{100})

ln (\frac{1}{1 - 0.6})

sec (3 x + 1) - ln (3 x)

ln (8.56 \cdot 1 0^{- 4})

What is 1/2 (ln(e^2+1)-ln(2)) ?
The solution to 1/2 (ln(e^2+1)-ln(2)) is 1/2 ln((e^2+1)/2)