What is log_{10}(6)log_{10}(2)+log_{10}(3) ?

The solution to log_{10}(6)log_{10}(2)+log_{10}(3) is log_{10}(2^{log_{10}(6)}*3)

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simplify log_{10}(6)log_{10}(2)+log_{10}(3)

simplify

lo g_{10} (6) lo g_{10} (2) + lo g_{10} (3)

lo g_{10} (2^{l o g_{10} (6)} \cdot 3)

Decimal Notation

0.71136 \dots

Solution steps

lo g_{10} (6) lo g_{10} (2) + lo g_{10} (3)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

lo g_{10} (6) lo g_{10} (2) = lo g_{10} (2^{l o g_{10} (6)})

= lo g_{10} (2^{l o g_{10} (6)}) + lo g_{10} (3)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (2^{l o g_{10} (6)}) + lo g_{10} (3) = lo g_{10} (3 \cdot 2^{l o g_{10} (6)})

= lo g_{10} (2^{l o g_{10} (6)} \cdot 3)

(\frac{1}{0.143}) ln (\frac{6 \cdot 1 0 ^{9}}{29000})

ln (\frac{547}{273}) \cdot 8

lo g_{0.3} (10) - lo g_{0.3} (3)

\frac{3}{4} lo g_{10} (7 + 43)

ln (\frac{2863}{1.0 8 ^{8}})

What is log_{10}(6)log_{10}(2)+log_{10}(3) ?
The solution to log_{10}(6)log_{10}(2)+log_{10}(3) is log_{10}(2^{log_{10}(6)}*3)