What is ln(((\sqrt[3]{y}))/(z*x^4)) ?

The solution to ln(((\sqrt[3]{y}))/(z*x^4)) is ln(\sqrt[3]{y})-ln(z)-4ln(x)

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simplify ln(((\sqrt[3]{y}))/(z*x^4))

simplify

Solution steps

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (z x^{4}) = ln (z) + ln (x^{4})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (x^{4}) = 4 ln (x)

- (ln (z) + 4 ln (x)) : - ln (z) - 4 ln (x)

ln (\frac{4}{245})

+ 2 ln (x) - 2 ln (y)

lo g_{2} (\frac{c ^{3}}{d})

ln (0.6 π)

7 ln (x y) - 5 ln (yz)

What is ln(((\sqrt[3]{y}))/(z*x^4)) ?
The solution to ln(((\sqrt[3]{y}))/(z*x^4)) is ln(\sqrt[3]{y})-ln(z)-4ln(x)