What is log_{10}(45129) ?

The solution to log_{10}(45129) is log_{10}(45)\circ+log_{10}(12)\circ+2log_{10}(3)\circ

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Popular >

simplify log_{10}(45129)

simplify

lo g_{10} (4 5^{\circ} 1 2^{\circ} 9^{\circ})

lo g_{10} (45) \circ + lo g_{10} (12) \circ + 2 lo g_{10} (3) \circ

Decimal Notation

3.68663 \dots

Solution steps

lo g_{10} (4 5^{\circ} \cdot 1 2^{\circ} \cdot 9^{\circ})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (4 5^{\circ} \cdot 1 2^{\circ} \cdot 9^{\circ}) = lo g_{10} (4 5^{\circ}) + lo g_{10} (1 2^{\circ}) + lo g_{10} (9^{\circ})

= lo g_{10} (4 5^{\circ}) + lo g_{10} (1 2^{\circ}) + lo g_{10} (9^{\circ})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (4 5^{\circ}) = \circ lo g_{10} (45)

= \circ lo g_{10} (45) + lo g_{10} (1 2^{\circ}) + lo g_{10} (9^{\circ})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (1 2^{\circ}) = \circ lo g_{10} (12)

= \circ lo g_{10} (45) + \circ lo g_{10} (12) + lo g_{10} (9^{\circ})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (9^{\circ}) = \circ lo g_{10} (9)

= \circ lo g_{10} (45) + \circ lo g_{10} (12) + \circ lo g_{10} (9)

Simplify

lo g_{10} (9) : 2 lo g_{10} (3)

= lo g_{10} (45) \circ + lo g_{10} (12) \circ + 2 lo g_{10} (3) \circ

- ln ∣ 2 x - 2 ∣ + ln ∣ 2 x - 4 ∣

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ln (\frac{2}{2 \cdot ( 1.42 \cdot 1 0 ^{(- 3)} )})

ln (\frac{1}{m} e^{\frac{- ( x - 2 )}{m}})

- 6 ln (2) + \frac{15}{2} - 6 (ln (3) - ln (2)) + \frac{7}{2}

What is log_{10}(45129) ?
The solution to log_{10}(45129) is log_{10}(45)\circ+log_{10}(12)\circ+2log_{10}(3)\circ