What is ln(1/(x(x+1)(x+2))) ?

The solution to ln(1/(x(x+1)(x+2))) is -(ln(x)+ln(x+1)+ln(x+2))

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simplify ln(1/(x(x+1)(x+2)))

simplify

ln (\frac{1}{x ( x + 1 ) ( x + 2 )})

- (ln (x) + ln (x + 1) + ln (x + 2))

Solution steps

ln (\frac{1}{x ( x + 1 ) ( x + 2 )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1}{x ( x + 1 ) ( x + 2 )}) = ln (1) - ln (x (x + 1) (x + 2))

= ln (1) - ln (x (x + 1) (x + 2))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (x (x + 1) (x + 2)) = ln (x) + ln (x + 1) + ln (x + 2)

= ln (1) - (ln (x) + ln (x + 1) + ln (x + 2))

Apply log rule:

lo g_{a} (1) = 0

= 0 - (ln (x) + ln (x + 1) + ln (x + 2))

0 - (ln (x) + ln (x + 1) + ln (x + 2)) = - (ln (x) + ln (x + 1) + ln (x + 2))

= - (ln (x) + ln (x + 1) + ln (x + 2))

- t^{2} + ln (5 t) + 15

ln (\frac{2.527}{2 x + 1}) - 5

ln (\frac{( x + 1 ) ( x + 2 )}{x + 3})

ln (sec (x) + tan (x)) - ln (sec (x))

ln (\frac{a ^{- 3}}{b ^{1} c ^{1}})

What is ln(1/(x(x+1)(x+2))) ?
The solution to ln(1/(x(x+1)(x+2))) is -(ln(x)+ln(x+1)+ln(x+2))