What is ln((t^2+1)^{1/2})+ln(k) ?

The solution to ln((t^2+1)^{1/2})+ln(k) is ln((t^2+1)^{1/2}k)

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simplify ln((t^2+1)^{1/2})+ln(k)

simplify

ln ((t^{2} + 1)^{\frac{1}{2}}) + ln (k)

ln ((t^{2} + 1)^{\frac{1}{2}} k)

Solution steps

ln ((t^{2} + 1)^{\frac{1}{2}}) + ln (k)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln ((t^{2} + 1)^{\frac{1}{2}}) + ln (k) = ln (k (t^{2} + 1)^{\frac{1}{2}})

= ln ((t^{2} + 1)^{\frac{1}{2}} k)

- \frac{1}{9} ln (\frac{100}{5})

ln (\frac{5 + 6}{2 + 3})

\frac{60}{2.2} ln (\frac{0.116}{0.035})

\frac{1}{2} \cdot ln (\frac{110}{125})

ln (\frac{30.6}{70.1})

What is ln((t^2+1)^{1/2})+ln(k) ?
The solution to ln((t^2+1)^{1/2})+ln(k) is ln((t^2+1)^{1/2}k)