What is factor log_{10}((x^9)/(y^4)) ?

The solution to factor log_{10}((x^9)/(y^4)) is 9log_{10}(x)-4log_{10}(y)

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factor log_{10}((x^9)/(y^4))

factor

lo g_{10} (\frac{x ^{9}}{y ^{4}})

9 lo g_{10} (x) - 4 lo g_{10} (y)

Solution steps

lo g_{10} (\frac{x ^{9}}{y ^{4}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{x ^{9}}{y ^{4}}) = lo g_{10} (x^{9}) - lo g_{10} (y^{4})

= lo g_{10} (x^{9}) - lo g_{10} (y^{4})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (x^{9}) = 9 lo g_{10} (x)

= 9 lo g_{10} (x) - lo g_{10} (y^{4})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (y^{4}) = 4 lo g_{10} (y)

= 9 lo g_{10} (x) - 4 lo g_{10} (y)

ln (\frac{3}{e ^{3}})

- 2 - x + ln 1 - \frac{1}{- 2 - x} + x + ln 1 - \frac{1}{x}

3 ln (x^{2}) + 5 ln (y) - 2 ln (a) + 4 ln (b^{3}) - 3 ln (c) + 2

\frac{125 \cdot 1.5 \cdot 1 0 ^{6}}{200 \cdot 25 \cdot 50} \cdot ln (\frac{150}{100})

10 \cdot lo g_{10} (\frac{2.7 x 1 0 ^{- 11}}{1 0 ^{- 12}})

What is factor log_{10}((x^9)/(y^4)) ?
The solution to factor log_{10}((x^9)/(y^4)) is 9log_{10}(x)-4log_{10}(y)