What are the solutions to the equation 2x^2-12x+14=0 ?

The solutions to the equation 2x^2-12x+14=0 are x=3+sqrt(2),x=3-sqrt(2)

Find the zeros of 2x^2-12x+14=0

The zeros of 2x^2-12x+14=0 are x=3+sqrt(2),x=3-sqrt(2)

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2 x^{2} - 12 x + 14 = 0

x = 3 + 2, x = 3 - 2

Decimal Notation

x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

2 x^{2} - 12 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 14 = 42

x_{1, 2} = \frac{- ( - 12 ) \pm 4 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 2}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 4 2}{2 \cdot 2}

x = \frac{- ( - 12 ) + 4 2}{2 \cdot 2} : 3 + 2

x = \frac{- ( - 12 ) - 4 2}{2 \cdot 2} : 3 - 2

The solutions to the quadratic equation are:

x = 3 + 2, x = 3 - 2

4 - (3 x - 9)^{2} = - 12

n^{3} - n^{2} + 3 n - 3

2 > 2

10 (x - 2) = - 20

\frac{1}{2} + \frac{1}{12}

What are the solutions to the equation 2x^2-12x+14=0 ?
The solutions to the equation 2x^2-12x+14=0 are x=3+sqrt(2),x=3-sqrt(2)
Find the zeros of 2x^2-12x+14=0
The zeros of 2x^2-12x+14=0 are x=3+sqrt(2),x=3-sqrt(2)