What is 2-4*(log_{e}(25)-log_{e}(13)) ?

The solution to 2-4*(log_{e}(25)-log_{e}(13)) is 2-4ln(25/13)

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simplify 2-4*(log_{e}(25)-log_{e}(13))

simplify

2 - 4 \cdot (lo g_{e} (25) - lo g_{e} (13))

2 - 4 ln (\frac{25}{13})

Decimal Notation

- 0.61570 \dots

Solution steps

2 - 4 (lo g_{e} (25) - lo g_{e} (13))

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{e} (25) - lo g_{e} (13) = lo g_{e} (\frac{25}{13})

= 2 - 4 lo g_{e} (\frac{25}{13})

Simplify

lo g_{e} (\frac{25}{13}) : ln (\frac{25}{13})

= 2 - 4 ln (\frac{25}{13})

ln (x) - ln (v) + ln (v^{2} + 12)

\frac{43 π}{10} + ln (7) - \frac{1}{2} \cdot ln (26) - 169760

ln (\frac{2 x}{e ^{2 x}})

\frac{1}{2} ln (x - 3) + \frac{1}{2} ln (x + 3) - ln (x)

4.74 + lo g_{10} (\frac{50}{10})

What is 2-4*(log_{e}(25)-log_{e}(13)) ?
The solution to 2-4*(log_{e}(25)-log_{e}(13)) is 2-4ln(25/13)