What is ln(2120)-ln(2120-10000)-ln(-1/249) ?

The solution to ln(2120)-ln(2120-10000)-ln(-1/249) is ln(13197/197)

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simplify ln(2120)-ln(2120-10000)-ln(-1/249)

simplify

ln (2120) - ln (2120 - 10000) - ln (- \frac{1}{249})

ln (\frac{13197}{197})

Decimal Notation

4.20454 \dots

Solution steps

ln (2120) - ln (2120 - 10000) - ln (- \frac{1}{249})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (2120) - ln (2120 - 10000) = ln (\frac{2120}{2120 - 10000})

= ln (\frac{2120}{2120 - 10000}) - ln (- \frac{1}{249})

\frac{2120}{2120 - 10000} = - \frac{53}{197}

= ln (- \frac{53}{197}) - ln (- \frac{1}{249})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (- \frac{53}{197}) - ln (- \frac{1}{249}) = ln (\frac{- \frac{53}{197}}{- \frac{1}{249}})

= ln (\frac{- \frac{53}{197}}{- \frac{1}{249}})

\frac{- \frac{53}{197}}{- \frac{1}{249}} = \frac{13197}{197}

= ln (\frac{13197}{197})

lo g_{10} (x) + \frac{1}{7} lo g_{10} (y)

(1 - (2 \cdot 0.93)) \cdot ln (\frac{1 - 0.93}{0.93})

lo g_{e} (\frac{e ^{a + b \cdot x} - f ( x )}{f ( x )})

ln (\frac{y}{x ^{2 n}} \cdot e^{\frac{- m}{x}})

ln (- 2 y d y)

What is ln(2120)-ln(2120-10000)-ln(-1/249) ?
The solution to ln(2120)-ln(2120-10000)-ln(-1/249) is ln(13197/197)