What is ln((2n^2+1)/(n^2+1)) ?

The solution to ln((2n^2+1)/(n^2+1)) is ln(2n^2+1)-ln(n^2+1)

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simplify ln((2n^2+1)/(n^2+1))

simplify

ln (\frac{2 n ^{2} + 1}{n ^{2} + 1})

ln (2 n^{2} + 1) - ln (n^{2} + 1)

Solution steps

ln (\frac{2 n ^{2} + 1}{n ^{2} + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{2 n ^{2} + 1}{n ^{2} + 1}) = ln (2 n^{2} + 1) - ln (n^{2} + 1)

= ln (2 n^{2} + 1) - ln (n^{2} + 1)

\frac{3}{2} ln (\frac{x - 1}{x + 2}) - 5

lo g_{10} (\frac{11 r ^{3}}{w})

2 lo g_{e} (9) + 2 lo g_{e} (π) - lo g_{e} (8)

\frac{1}{2} ln (\frac{2 - 1}{2 + 1})

ln (\frac{47}{50}) + (0.085) \cdot 0.054

What is ln((2n^2+1)/(n^2+1)) ?
The solution to ln((2n^2+1)/(n^2+1)) is ln(2n^2+1)-ln(n^2+1)