What is log_{1.8}((6.69)/(3.12))+53.29-54.01 ?

The solution to log_{1.8}((6.69)/(3.12))+53.29-54.01 is log_{1.8}(6.69)-0.72-log_{1.8}(3.12)

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simplify log_{1.8}((6.69)/(3.12))+53.29-54.01

simplify

lo g_{1.8} (\frac{6.69}{3.12}) + 53.29 - 54.01

lo g_{1.8} (6.69) - 0.72 - lo g_{1.8} (3.12)

Decimal Notation

0.57771 \dots

Solution steps

lo g_{1.8} (\frac{6.69}{3.12}) + 53.29 - 54.01

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{1.8} (\frac{6.69}{3.12}) = lo g_{1.8} (6.69) - lo g_{1.8} (3.12)

= lo g_{1.8} (6.69) - lo g_{1.8} (3.12) + 53.29 - 54.01

Add/Subtract the numbers:

53.29 - 54.01 = - 0.72

= lo g_{1.8} (6.69) - 0.72 - lo g_{1.8} (3.12)

10 lo g_{10} (\frac{2 \cdot 1 0 ^{- 6}}{1 0 ^{- 12}})

9 ln (x + 6) - 7 ln (x)

ln (θ e^{- θ (x - 1)})

16 + 4 ln (5) - 4 ln (3)

ln (\frac{( a - b )}{c})

What is log_{1.8}((6.69)/(3.12))+53.29-54.01 ?
The solution to log_{1.8}((6.69)/(3.12))+53.29-54.01 is log_{1.8}(6.69)-0.72-log_{1.8}(3.12)