What is log_{10}(1.42*10^{-5})-(2.84*10^{-10}) ?

The solution to log_{10}(1.42*10^{-5})-(2.84*10^{-10}) is log_{10}(142)-7-(71)/(25*10^{10)}

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simplify log_{10}(1.4210^{-5})-(2.8410^{-10})

simplify

lo g_{10} (1.42 \cdot 1 0^{- 5}) - (2.84 \cdot 1 0^{- 10})

lo g_{10} (142) - 7 - \frac{71}{25 \cdot 1 0 ^{10}}

Decimal Notation

- 4.84771 \dots

Solution steps

lo g_{10} (1.42 \cdot 1 0^{- 5}) - (2.84 \cdot 1 0^{- 10})

Apply rule:

- (a) = - a

- (2.84 \cdot 1 0^{- 10}) = - 2.84 \cdot 1 0^{- 10}

= lo g_{10} (1.42 \cdot 1 0^{- 5}) - 2.84 \cdot 1 0^{- 10}

lo g_{10} (1.42 \cdot 1 0^{- 5}) = lo g_{10} (142) - 7

2.84 \cdot 1 0^{- 10} = 2.84 \cdot \frac{1}{1 0 ^{10}}

= lo g_{10} (142) - 7 - 2.84 \cdot \frac{1}{1 0 ^{10}}

2.84 \cdot \frac{1}{1 0 ^{10}} = \frac{284}{100 \cdot 1 0 ^{10}}

= lo g_{10} (142) - 7 - \frac{284}{100 \cdot 1 0 ^{10}}

Cancel

\frac{284}{100 \cdot 1 0 ^{10}} : \frac{71}{25 \cdot 1 0 ^{10}}

= lo g_{10} (142) - 7 - \frac{71}{25 \cdot 1 0 ^{10}}

ln (\frac{1.25}{0.2})

ln (\frac{7.63}{600})

lo g_{2} (x - 6) + lo g_{2} (x - 4) - lo g_{2} (x)

ln (\frac{y}{x} + 4) - 6 ln (\frac{y}{x} - 1)

What is log_{10}(1.42*10^{-5})-(2.84*10^{-10}) ?
The solution to log_{10}(1.42*10^{-5})-(2.84*10^{-10}) is log_{10}(142)-7-(71)/(25*10^{10)}