What are the solutions to the equation 0.5X^2+1.5X-2=0 ?

The solutions to the equation 0.5X^2+1.5X-2=0 are X=1,X=-4

Find the zeros of 0.5X^2+1.5X-2=0

The zeros of 0.5X^2+1.5X-2=0 are X=1,X=-4

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0.5 X^{2} + 1.5 X - 2 = 0

X = 1, X = - 4

Solution steps

0.5 X^{2} + 1.5 X - 2 = 0

Multiply both sides by

10

5 X^{2} + 15 X - 20 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 ( - 20 )}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 (- 20) = 25

X_{1, 2} = \frac{- 15 \pm 25}{2 \cdot 5}

Separate the solutions

X_{1} = \frac{- 15 + 25}{2 \cdot 5}, X_{2} = \frac{- 15 - 25}{2 \cdot 5}

X = \frac{- 15 + 25}{2 \cdot 5} : 1

X = \frac{- 15 - 25}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

X = 1, X = - 4

x^{- \frac{1}{2}}

(x - 8)^{2} = 25

(m - n)^{2} - (2 m + 3 n)^{2}

- \frac{2}{3} (- 3)

15 (1.2)^{10}

What are the solutions to the equation 0.5X^2+1.5X-2=0 ?
The solutions to the equation 0.5X^2+1.5X-2=0 are X=1,X=-4
Find the zeros of 0.5X^2+1.5X-2=0
The zeros of 0.5X^2+1.5X-2=0 are X=1,X=-4