What is ln(((xt)^2+(yt)^2)/(tx+ty)) ?

The solution to ln(((xt)^2+(yt)^2)/(tx+ty)) is ln(x^2t^2+t^2y^2)-ln(xt+ty)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln(((xt)^2+(yt)^2)/(tx+ty))

simplify

ln (\frac{( x t ) ^{2} + ( y t ) ^{2}}{t x + t y})

ln (x^{2} t^{2} + t^{2} y^{2}) - ln (x t + t y)

Solution steps

ln (\frac{( x t ) ^{2} + ( y t ) ^{2}}{t x + t y})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( x t ) ^{2} + ( y t ) ^{2}}{t x + t y}) = ln ((x t)^{2} + (y t)^{2}) - ln (t x + t y)

= ln ((x t)^{2} + (t y)^{2}) - ln (x t + t y)

ln ((x t)^{2} + (y t)^{2}) = ln (x^{2} t^{2} + t^{2} y^{2})

= ln (x^{2} t^{2} + t^{2} y^{2}) - ln (x t + t y)

ln (\frac{0.023}{0.02})

- \frac{1}{2} ln (6)

- 20 lo g_{10} (\frac{0.125}{4 π \cdot 5000})

ln (\frac{1000}{1042})

ln (v) - ln (x)

What is ln(((xt)^2+(yt)^2)/(tx+ty)) ?
The solution to ln(((xt)^2+(yt)^2)/(tx+ty)) is ln(x^2t^2+t^2y^2)-ln(xt+ty)