What is 4x^2+2/(7x)-ln(3x) ?

The solution to 4x^2+2/(7x)-ln(3x) is 4x^2+2/(7x)-ln(3)-ln(x)

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simplify 4x^2+2/(7x)-ln(3x)

simplify

4 x^{2} + \frac{2}{7 x} - ln (3 x)

4 x^{2} + \frac{2}{7 x} - ln (3) - ln (x)

Solution steps

4 x^{2} + \frac{2}{7 x} - ln (3 x)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (3 x) = ln (3) + ln (x)

= 4 x^{2} + \frac{2}{7 x} - (ln (x) + ln (3))

- (ln (3) + ln (x)) : - ln (3) - ln (x)

= 4 x^{2} + \frac{2}{7 x} - ln (3) - ln (x)

ln (\frac{1.011 \cdot 1 0 ^{4}}{1})

2 lo g_{10} (x) - \frac{1}{2} lo g_{10} (x - 2)

- ln (2) + ln (10) - 2 ln (3)

7 ln (x) - ln (x^{2} - 25)

What is 4x^2+2/(7x)-ln(3x) ?
The solution to 4x^2+2/(7x)-ln(3x) is 4x^2+2/(7x)-ln(3)-ln(x)