What is log_{10}((10)/(1+4e^{-0.8x)}) ?

The solution to log_{10}((10)/(1+4e^{-0.8x)}) is 1-log_{10}(1+4e^{-0.8x})

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simplify log_{10}((10)/(1+4e^{-0.8x)})

simplify

lo g_{10} (\frac{10}{1 + 4 e ^{- 0.8 x}})

1 - lo g_{10} (1 + 4 e^{- 0.8 x})

Solution steps

lo g_{10} (\frac{10}{1 + 4 e ^{- 0.8 x}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{10}{1 + 4 e ^{- 0.8 x}}) = lo g_{10} (10) - lo g_{10} (1 + 4 e^{- 0.8 x})

= lo g_{10} (10) - lo g_{10} (4 e^{- 0.8 x} + 1)

Apply log rule:

lo g_{a} (a) = 1

= 1 - lo g_{10} (4 e^{- 0.8 x} + 1)

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What is log_{10}((10)/(1+4e^{-0.8x)}) ?
The solution to log_{10}((10)/(1+4e^{-0.8x)}) is 1-log_{10}(1+4e^{-0.8x})