What is ln(2x)+1/(x^2)-2e^{2x} ?

The solution to ln(2x)+1/(x^2)-2e^{2x} is ln(2)+ln(x)+1/(x^2)-2e^{2x}

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simplify ln(2x)+1/(x^2)-2e^{2x}

simplify

ln (2 x) + \frac{1}{x ^{2}} - 2 e^{2 x}

ln (2) + ln (x) + \frac{1}{x ^{2}} - 2 e^{2 x}

Solution steps

ln (2 x) + \frac{1}{x ^{2}} - 2 e^{2 x}

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (2 x) = ln (2) + ln (x)

= ln (2) + ln (x) + \frac{1}{x ^{2}} - 2 e^{2 x}

ln (6) + ln (\frac{e ^{(2.39209)}}{3})

\frac{1}{2} ln (3) - \frac{1}{2} ln (2)

ln (\frac{2.1 x 1 0 ^{- 4} x}{0.9025})

\frac{1}{398} ln (\frac{250}{238})

9.25 + lo g_{10} (\frac{0.18}{0.26})

What is ln(2x)+1/(x^2)-2e^{2x} ?
The solution to ln(2x)+1/(x^2)-2e^{2x} is ln(2)+ln(x)+1/(x^2)-2e^{2x}