What is factor log_{8}(2-x)+log_{8}(4-x) ?

The solution to factor log_{8}(2-x)+log_{8}(4-x) is log_{8}((2-x)(4-x))

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factor log_{8}(2-x)+log_{8}(4-x)

factor

lo g_{8} (2 - x) + lo g_{8} (4 - x)

lo g_{8} ((2 - x) (4 - x))

Solution steps

lo g_{8} (2 - x) + lo g_{8} (4 - x)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{8} (2 - x) + lo g_{8} (4 - x) = lo g_{8} ((- x + 2) (- x + 4))

= lo g_{8} ((2 - x) (4 - x))

0.2 ln (30) + 0.8 ln (5)

- \frac{( 1 )}{( 2 )} ln^{4} (x^{2}) - \frac{( 1 )}{( 2 )} ln (x^{2})

lo g_{5} ((\frac{x}{2 y})^{8})

\frac{( ln ( 0.25 ) + ln ( 0.5 ) + ln ( 0.75 ) ) \cdot 2 \cdot 0.25}{2}

What is factor log_{8}(2-x)+log_{8}(4-x) ?
The solution to factor log_{8}(2-x)+log_{8}(4-x) is log_{8}((2-x)(4-x))