What are the solutions to the equation 4v^2=-20v ?

The solutions to the equation 4v^2=-20v are v=0,v=-5

Find the zeros of 4v^2=-20v

The zeros of 4v^2=-20v are v=0,v=-5

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4 v^{2} = - 20 v

v = 0, v = - 5

Solution steps

4 v^{2} = - 20 v

Move

20 v

to the left side

4 v^{2} + 20 v = 0

Factor

4 v^{2} + 20 v : 4 v (v + 5)

4 v (v + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

v = 0 or v + 5 = 0

Solve

v + 5 = 0 : v = - 5

The solutions to the quadratic equation are:

v = 0, v = - 5

4 x^{4} - 24 x^{3} + 36 x^{2}

4 x + 2 (2 x - 5) = (x - 3) - (8 - x)

2 x + 4 = 5

1 + x^{3}

\frac{1}{6} \cdot \frac{3}{5}

What are the solutions to the equation 4v^2=-20v ?
The solutions to the equation 4v^2=-20v are v=0,v=-5
Find the zeros of 4v^2=-20v
The zeros of 4v^2=-20v are v=0,v=-5