What is simplify-0.25ln(1.33813sqrt(2.5^2+0.55848)) ?

The solution to simplify-0.25ln(1.33813sqrt(2.5^2+0.55848)) is -0.25ln(1.33813)-(0.25ln(6.80848))/2

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simplify-0.25ln(1.33813sqrt(2.5^2+0.55848))

simplify

- 0.25 ln (1.33813 2. 5^{2} + 0.55848)

- 0.25 ln (1.33813) - \frac{0.25 ln ( 6.80848 )}{2}

Decimal Notation

- 0.31258 \dots

Solution steps

- 0.25 ln (1.33813 2. 5^{2} + 0.55848)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

0.25 ln (1.33813 2. 5^{2} + 0.55848) = 0.25 ln (1.33813) + 0.25 ln (2. 5^{2} + 0.55848)

= - (0.25 ln (1.33813) + 0.25 ln (0.55848 + 2. 5^{2}))

0.25 ln (2. 5^{2} + 0.55848) = 0.25 \cdot \frac{ln ( 6.80848 )}{2}

= - (0.25 ln (1.33813) + 0.25 \cdot \frac{ln ( 6.80848 )}{2})

Multiply

0.25 \cdot \frac{ln ( 6.80848 )}{2} : \frac{0.25 ln ( 6.80848 )}{2}

= - (0.25 ln (1.33813) + \frac{0.25 ln ( 6.80848 )}{2})

= - (0.25 ln (1.33813) + \frac{0.25 ln ( 6.80848 )}{2})

Distribute parentheses

= - (0.25 ln (1.33813)) - (\frac{ln ( 6.80848 ) \cdot 0.25}{2})

Apply minus-plus rules

+ (- a) = - a

= - 0.25 ln (1.33813) - \frac{ln ( 6.80848 ) \cdot 0.25}{2}

ln (\frac{2.01}{1.7})

4.8 + lo g_{10} (\frac{( 0.008 )}{( 0.012 )})

- 200 (ln (40) - ln (50))

ln (\frac{684}{760})

lo g_{10} (\frac{a ^{2} b ^{3}}{c ^{4}})

What is simplify-0.25ln(1.33813sqrt(2.5^2+0.55848)) ?
The solution to simplify-0.25ln(1.33813sqrt(2.5^2+0.55848)) is -0.25ln(1.33813)-(0.25ln(6.80848))/2