What is pi^{16}ln((2+29^{1/2})/5) ?

The solution to pi^{16}ln((2+29^{1/2})/5) is pi^{16}(ln(2+29^{1/2})-ln(5))

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simplify pi^{16}ln((2+29^{1/2})/5)

simplify

π^{16} ln (\frac{2 + 2 9 ^{\frac{1}{2}}}{5})

π^{16} (ln (2 + 2 9^{\frac{1}{2}}) - ln (5))

Decimal Notation

35115746.04614 \dots

Solution steps

π^{16} ln (\frac{2 + 2 9 ^{\frac{1}{2}}}{5})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{2 + 2 9 ^{\frac{1}{2}}}{5}) = ln (2 + 2 9^{\frac{1}{2}}) - ln (5)

= π^{16} (ln (2 + 2 9^{\frac{1}{2}}) - ln (5))

4 ln (1 + \frac{9 i}{n})

\frac{1}{4} ln (\frac{1}{2})

\frac{3}{2} ln (4 x^{8}) - \frac{2}{5} ln (2 y^{20})

2 [ln (x) - ln (x + 5) - ln (x - 5)]

ln (\frac{4}{e ^{3 x - 1}})

What is pi^{16}ln((2+29^{1/2})/5) ?
The solution to pi^{16}ln((2+29^{1/2})/5) is pi^{16}(ln(2+29^{1/2})-ln(5))