What is ln(x(1-e^{-t/y})) ?

The solution to ln(x(1-e^{-t/y})) is ln(x)+ln(1-e^{-t/y})

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simplify ln(x(1-e^{-t/y}))

simplify

ln (x (1 - e^{- \frac{t}{y}}))

ln (x) + ln (1 - e^{- \frac{t}{y}})

Solution steps

ln (x (1 - e^{- \frac{t}{y}}))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (x (1 - e^{- \frac{t}{y}})) = ln (x) + ln (1 - e^{- \frac{t}{y}})

= ln (x) + ln (- e^{- \frac{t}{y}} + 1)

lo g_{10} (3 m^{4} n^{- 2})

\frac{- 1}{42} ln (\frac{74}{100})

ln ((2 e^{b D} cosh (b u h) + 1)^{N})

ln ∣ x ∣ - ln ∣ x - 50 ∣

2 ln (x - 2) + ln (3) - ln (x^{2} - 4)

What is ln(x(1-e^{-t/y})) ?
The solution to ln(x(1-e^{-t/y})) is ln(x)+ln(1-e^{-t/y})