What are the solutions to the equation y^2-2y-24=0 ?

The solutions to the equation y^2-2y-24=0 are y=6,y=-4

Find the zeros of y^2-2y-24=0

The zeros of y^2-2y-24=0 are y=6,y=-4

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y^{2} - 2 y - 24 = 0

y = 6, y = - 4

Solution steps

y^{2} - 2 y - 24 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

y_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

y = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

y = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

y = 6, y = - 4

4 x - 3 + 2 x = 5 (2 x - 3)

\frac{1}{2} + \frac{1}{4} - \frac{2}{6} - \frac{3}{8}

c = 180 (6) + 250

\frac{1 - x ^{2}}{x + 2} \geq 0

3 x^{2} + 8 x = 0

What are the solutions to the equation y^2-2y-24=0 ?
The solutions to the equation y^2-2y-24=0 are y=6,y=-4
Find the zeros of y^2-2y-24=0
The zeros of y^2-2y-24=0 are y=6,y=-4