What is 5log_{h}(y)+4log_{h}(x) ?

The solution to 5log_{h}(y)+4log_{h}(x) is log_{h}(y^5x^4)

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simplify 5log_{h}(y)+4log_{h}(x)

simplify

5 lo g_{h} (y) + 4 lo g_{h} (x)

lo g_{h} (y^{5} x^{4})

Solution steps

5 lo g_{h} (y) + 4 lo g_{h} (x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

5 lo g_{h} (y) = lo g_{h} (y^{5})

= lo g_{h} (y^{5}) + 4 lo g_{h} (x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{h} (x) = lo g_{h} (x^{4})

= lo g_{h} (y^{5}) + lo g_{h} (x^{4})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{h} (y^{5}) + lo g_{h} (x^{4}) = lo g_{h} (y^{5} x^{4})

= lo g_{h} (y^{5} x^{4})

- \frac{1}{3} ln ∣ x + 1 ∣ + \frac{1}{3} ln ∣ x - 2 ∣ + 3

ln (6) + ln (\frac{e ^{(2.43849)}}{3})

ln (7 (- 4)^{2} (2) (3))

ln (\frac{96}{7}) + \frac{1}{2} (ln (\frac{2}{3} x)) + \frac{1}{4} (ln (\frac{15}{8}))

lo g_{10} (2 π \cdot 1606 \cdot 5.03 \cdot 9.566)

What is 5log_{h}(y)+4log_{h}(x) ?
The solution to 5log_{h}(y)+4log_{h}(x) is log_{h}(y^5x^4)