What is log_{10}(3-x)+log_{10}(4-x^2) ?

The solution to log_{10}(3-x)+log_{10}(4-x^2) is log_{10}((3-x)(4-x^2))

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simplify log_{10}(3-x)+log_{10}(4-x^2)

simplify

lo g_{10} (3 - x) + lo g_{10} (4 - x^{2})

lo g_{10} ((3 - x) (4 - x^{2}))

Solution steps

lo g_{10} (3 - x) + lo g_{10} (4 - x^{2})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (3 - x) + lo g_{10} (4 - x^{2}) = lo g_{10} ((- x + 3) (- x^{2} + 4))

= lo g_{10} ((3 - x) (4 - x^{2}))

ln (13) - ln (7)

\frac{1}{2} lo g_{3} (x) + \frac{2}{3} lo g_{3} (y)

3 ln (x y)

e^{(\frac{5}{4} (l n (x) - l n (5 x - 4)) + c)}

What is log_{10}(3-x)+log_{10}(4-x^2) ?
The solution to log_{10}(3-x)+log_{10}(4-x^2) is log_{10}((3-x)(4-x^2))