What is 4log_{8}(u)-2log_{8}(v) ?

The solution to 4log_{8}(u)-2log_{8}(v) is log_{8}((u^4)/(v^2))

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simplify 4log_{8}(u)-2log_{8}(v)

simplify

4 lo g_{8} (u) - 2 lo g_{8} (v)

lo g_{8} (\frac{u ^{4}}{v ^{2}})

Solution steps

4 lo g_{8} (u) - 2 lo g_{8} (v)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{8} (u) = lo g_{8} (u^{4})

= lo g_{8} (u^{4}) - 2 lo g_{8} (v)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{8} (v) = lo g_{8} (v^{2})

= lo g_{8} (u^{4}) - lo g_{8} (v^{2})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{8} (u^{4}) - lo g_{8} (v^{2}) = lo g_{8} (\frac{u ^{4}}{v ^{2}})

= lo g_{8} (\frac{u ^{4}}{v ^{2}})

ln (\frac{115}{120})

lo g_{b} (x) - 2 lo g_{b} (y)

\frac{1}{2} ln (2 x + 5) - \frac{1}{3} ln (x + 3) + ln (C)

ln (i (2 + 6))

ln (6) + ln (\frac{e ^{(2.46169)}}{3})

What is 4log_{8}(u)-2log_{8}(v) ?
The solution to 4log_{8}(u)-2log_{8}(v) is log_{8}((u^4)/(v^2))