What is ln((1+e^x)/(1-e^x)) ?

The solution to ln((1+e^x)/(1-e^x)) is ln(1+e^x)-ln(1-e^x)

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simplify ln((1+e^x)/(1-e^x))

simplify

ln (\frac{1 + e ^{x}}{1 - e ^{x}})

ln (1 + e^{x}) - ln (1 - e^{x})

Solution steps

ln (\frac{1 + e ^{x}}{1 - e ^{x}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1 + e ^{x}}{1 - e ^{x}}) = ln (1 + e^{x}) - ln (1 - e^{x})

= ln (e^{x} + 1) - ln (- e^{x} + 1)

\frac{1}{6} (ln ∣ x ∣ - ln (x + 6))

2 ln (x) - 4 lo g_{e} (\frac{1}{y}) - 3 lo g_{e} (x) y

3 ln (5) - \frac{1}{2} ln (4) + ln (8)

lo g_{4} (\frac{4 a}{b})

10.64 + lo g_{10} (\frac{0.13}{0.25})

What is ln((1+e^x)/(1-e^x)) ?
The solution to ln((1+e^x)/(1-e^x)) is ln(1+e^x)-ln(1-e^x)