What is expand 2-(0, 25693/6)log_{e}(10^{-4}) ?

The solution to expand 2-(0, 25693/6)log_{e}(10^{-4}) is 2-(0, 25693/6)-4log_{e}(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2-(0, 25693/6)log_{e}(10^{-4})

expand

2 - (0, \frac{25693}{6}) lo g_{e} (1 0^{- 4})

2 - (0, \frac{25693}{6}) - 4 lo g_{e} (10)

Solution steps

2 - (0, \frac{25693}{6}) lo g_{e} (1 0^{- 4})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{e} (1 0^{- 4}) = - 4 lo g_{e} (10)

= 2 - (0, \frac{25693}{6}) - 4 lo g_{e} (10)

ln (0.906 \cdot 0.921 \cdot 0.971 \cdot 0.598 \cdot 0.983 \cdot 0.937)

ln (x) + 3 ln (x - 3) - 3 ln (x + 3)

ln ∣ 1 - 5 ∣ - ln ∣ 1 - 4 ∣ + 1

\frac{9}{2} - 9 ln (4) + 9 ln (3)

\frac{d ^{4}}{d x ^{4}} (e^{- 4 x}) + 6 ln (3 x^{5})

What is expand 2-(0, 25693/6)log_{e}(10^{-4}) ?
The solution to expand 2-(0, 25693/6)log_{e}(10^{-4}) is 2-(0, 25693/6)-4log_{e}(10)