What is 0.53-((0.0592)/2)*log_{10}((0.1)/3) ?

The solution to 0.53-((0.0592)/2)*log_{10}((0.1)/3) is 53/100+37/1250 log_{10}(30)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 0.53-((0.0592)/2)*log_{10}((0.1)/3)

simplify

0.53 - (\frac{0.0592}{2}) \cdot lo g_{10} (\frac{0.1}{3})

\frac{53}{100} + \frac{37}{1250} lo g_{10} (30)

Decimal Notation

0.57372 \dots

Solution steps

0.53 - (\frac{0.0592}{2}) lo g_{10} (\frac{0.1}{3})

0.53 = \frac{53}{100}

= \frac{53}{100} - \frac{0.0592}{2} lo g_{10} (\frac{0.1}{3})

\frac{0.0592}{2} = \frac{592}{20000}

= \frac{53}{100} - \frac{592}{20000} lo g_{10} (\frac{0.1}{3})

\frac{592}{20000} lo g_{10} (\frac{0.1}{3}) = - \frac{37}{1250} lo g_{10} (30)

= \frac{53}{100} - (- \frac{37}{1250} lo g_{10} (30))

Apply rule:

a - (- b) = a + b

\frac{53}{100} - (- \frac{37}{1250} lo g_{10} (30)) = \frac{53}{100} + \frac{37}{1250} lo g_{10} (30)

= \frac{53}{100} + \frac{37}{1250} lo g_{10} (30)

ln (\frac{24 2}{2})

- lo g_{10} (5.45 \cdot 1 0^{- 5})

lo g_{5} (\frac{2 x ^{3}}{4 y})

\frac{3}{2} + ln (2) - ln (3) + 2 ln (3) - 3 ln (2)

ln (0.005) - ln (0.05)

What is 0.53-((0.0592)/2)*log_{10}((0.1)/3) ?
The solution to 0.53-((0.0592)/2)*log_{10}((0.1)/3) is 53/100+37/1250 log_{10}(30)