What is e^{(ln(3)+ln(5))/2} ?

The solution to e^{(ln(3)+ln(5))/2} is e^{(ln(15))/2}

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simplify e^{(ln(3)+ln(5))/2}

simplify

e^{\frac{l n ( 3 ) + l n ( 5 )}{2}}

e^{\frac{l n ( 15 )}{2}}

Decimal Notation

3.87298 \dots

Solution steps

e^{\frac{l n ( 3 ) + l n ( 5 )}{2}}

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (3) + ln (5) = ln (3 \cdot 5)

= e^{\frac{l n ( 3 \cdot 5 )}{2}}

Multiply the numbers:

3 \cdot 5 = 15

= e^{\frac{l n ( 15 )}{2}}

7 lo g_{m} (z) - \frac{1}{2} lo g_{m} (w) + 5 lo g_{m} (x)

0 ln (\frac{\frac{20000}{17} - 1}{1199})

lo g_{e} (\frac{e ^{2} - 2 e ^{a + 2 b}}{1 - 2 e ^{a + 2 b}})

10 ln (\frac{47}{4})

ln (\frac{g}{2 \cdot v ^{2}})

What is e^{(ln(3)+ln(5))/2} ?
The solution to e^{(ln(3)+ln(5))/2} is e^{(ln(15))/2}