What is (pi/4)/2 (ln(2)+ln(3)) ?

The solution to (pi/4)/2 (ln(2)+ln(3)) is pi/8 ln(6)

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simplify (pi/4)/2 (ln(2)+ln(3))

simplify

\frac{\frac{π}{4}}{2} (ln (2) + ln (3))

\frac{π}{8} ln (6)

Decimal Notation

0.70362 \dots

Solution steps

\frac{\frac{π}{4}}{2} (ln (2) + ln (3))

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (2) + ln (3) = ln (2 \cdot 3)

= \frac{\frac{π}{4}}{2} ln (2 \cdot 3)

Multiply the numbers:

2 \cdot 3 = 6

= \frac{\frac{π}{4}}{2} ln (6)

\frac{\frac{π}{4}}{2} = \frac{π}{8}

= \frac{π}{8} ln (6)

ln ((\frac{e ^{3 x} ( x + 1 )}{2 x ^{2}})^{3})

ln (x) - \frac{1}{2} ln (x^{2} + 9)

4 ln (x) - ln (1 + x) + ln (1 - x)

ln (\frac{x ^{2}}{x + 1})

ln (\frac{100 + 1.84}{1.84})

What is (pi/4)/2 (ln(2)+ln(3)) ?
The solution to (pi/4)/2 (ln(2)+ln(3)) is pi/8 ln(6)