What is 13log_{10}(a)-log_{10}(b) ?

The solution to 13log_{10}(a)-log_{10}(b) is log_{10}((a^{13})/b)

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simplify 13log_{10}(a)-log_{10}(b)

simplify

13 lo g_{10} (a) - lo g_{10} (b)

lo g_{10} (\frac{a ^{13}}{b})

Solution steps

13 lo g_{10} (a) - lo g_{10} (b)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

13 lo g_{10} (a) = lo g_{10} (a^{13})

= lo g_{10} (a^{13}) - lo g_{10} (b)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (a^{13}) - lo g_{10} (b) = lo g_{10} (\frac{a ^{13}}{b})

= lo g_{10} (\frac{a ^{13}}{b})

ln (\frac{x ^{2}}{x ^{2} + 1}) - \frac{1}{x} - arctan (x) + c

1 - ln (\frac{3}{2})

ln (\frac{ln ( 2 )}{4})

ln (y^{5} x^{6})

- lo g_{10} (1.64 \cdot 1 0^{- 2})

What is 13log_{10}(a)-log_{10}(b) ?
The solution to 13log_{10}(a)-log_{10}(b) is log_{10}((a^{13})/b)