What are the solutions to the equation w^2+20=0 ?

The solutions to the equation w^2+20=0 are w=2sqrt(5)i,w=-2sqrt(5)i

Find the zeros of w^2+20=0

The zeros of w^2+20=0 are w=2sqrt(5)i,w=-2sqrt(5)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

w^{2} + 20 = 0

w = 25 i, w = - 25 i

Solution steps

w^{2} + 20 = 0

Move

20

to the right side

w^{2} = - 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = - 20, w = - - 20

- 20 = 25 i

- - 20 = - 25 i

w = 25 i, w = - 25 i

2 x^{2} - 7 x y + 3 y^{2}

\frac{4 ( k ) ^{4}}{3 k ^{9}}

6 y^{3} + 7 y^{2} + 2 y

\frac{1}{( \frac{π}{4} )}

y^{2} - 9 y + 9 = 0

What are the solutions to the equation w^2+20=0 ?
The solutions to the equation w^2+20=0 are w=2sqrt(5)i,w=-2sqrt(5)i
Find the zeros of w^2+20=0
The zeros of w^2+20=0 are w=2sqrt(5)i,w=-2sqrt(5)i