What is ln((1-e^x)/(1+e^x)) ?

The solution to ln((1-e^x)/(1+e^x)) is ln(1-e^x)-ln(1+e^x)

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simplify ln((1-e^x)/(1+e^x))

simplify

ln (\frac{1 - e ^{x}}{1 + e ^{x}})

ln (1 - e^{x}) - ln (1 + e^{x})

Solution steps

ln (\frac{1 - e ^{x}}{1 + e ^{x}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1 - e ^{x}}{1 + e ^{x}}) = ln (1 - e^{x}) - ln (1 + e^{x})

= ln (- e^{x} + 1) - ln (e^{x} + 1)

(ln (1) - ln (12)) + ln (M) + ln (L^{2})

- ln (2) + ln (7) - ln (6)

- \frac{1}{2} ln (\frac{y}{x}) - ln (x)

ln (2 (\frac{1}{9})^{2}) - 18 \cdot \frac{1}{9}

5 lo g_{e} (2) + 7 lo g_{e} (x) + 4 lo g_{e} (y)

What is ln((1-e^x)/(1+e^x)) ?
The solution to ln((1-e^x)/(1+e^x)) is ln(1-e^x)-ln(1+e^x)