What is log_{10}(0.1886)-log_{10}(0.2) ?

The solution to log_{10}(0.1886)-log_{10}(0.2) is log_{10}(943)-3

Popular >

simplify log_{10}(0.1886)-log_{10}(0.2)

simplify

lo g_{10} (0.1886) - lo g_{10} (0.2)

lo g_{10} (943) - 3

Decimal Notation

- 0.02548 \dots

Solution steps

lo g_{10} (0.1886) - lo g_{10} (0.2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (0.1886) - lo g_{10} (0.2) = lo g_{10} (\frac{0.1886}{0.2})

= lo g_{10} (\frac{0.1886}{0.2})

\frac{0.1886}{0.2} = \frac{943}{1000}

= lo g_{10} (\frac{943}{1000})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{943}{1000}) = lo g_{10} (943) - lo g_{10} (1000)

= lo g_{10} (943) - lo g_{10} (1000)

Simplify

lo g_{10} (1000) : 3

= lo g_{10} (943) - 3

2 ln (e^{2 x} sin (x))

ln (0.8 e^{- x} x)

\frac{- 2 y}{x ( 2 + ln ( y ) - ln ( x ) )}

ln (\frac{1}{3} x)

- 4 (ln (4 + 16 - x^{2}) - ln (x))

What is log_{10}(0.1886)-log_{10}(0.2) ?
The solution to log_{10}(0.1886)-log_{10}(0.2) is log_{10}(943)-3