What is expand log_{b}(y/(10)) ?

The solution to expand log_{b}(y/(10)) is log_{b}(y)-log_{b}(10)

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expand log_{b}(y/(10))

expand

lo g_{b} (\frac{y}{10})

lo g_{b} (y) - lo g_{b} (10)

Solution steps

lo g_{b} (\frac{y}{10})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{b} (\frac{y}{10}) = lo g_{b} (y) - lo g_{b} (10)

= lo g_{b} (y) - lo g_{b} (10)

2 lo g_{3} (x) - lo g_{3} (x + 2)

2 ln (x) - 4 ln (c)

3 ln (3 (1)) - 4

ln (\frac{( n + 2 ) ^{3} ( p + m ) ^{\frac{1}{5}}}{2 m ( m - n ) ^{\frac{1}{2}}})

- ln (\frac{36}{25})

What is expand log_{b}(y/(10)) ?
The solution to expand log_{b}(y/(10)) is log_{b}(y)-log_{b}(10)