What is ln(n^2+k^2)-ln(n^2) ?

The solution to ln(n^2+k^2)-ln(n^2) is ln((n^2+k^2)/(n^2))

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simplify ln(n^2+k^2)-ln(n^2)

simplify

ln (n^{2} + k^{2}) - ln (n^{2})

ln (\frac{n ^{2} + k ^{2}}{n ^{2}})

Solution steps

ln (n^{2} + k^{2}) - ln (n^{2})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (n^{2} + k^{2}) - ln (n^{2}) = ln (\frac{n ^{2} + k ^{2}}{n ^{2}})

= ln (\frac{n ^{2} + k ^{2}}{n ^{2}})

2 ln (2) + 2 β + 2 ln (x) + 3 e^{β} x

- \frac{1}{2} ln 2 \cdot 2^{2} + 4 \cdot 2 + 3 - ln (2)

- ln (\frac{33}{9})

ln (\frac{( 7 - x )}{( 7 + x )})

ln (5) + 2 ln (x) - 3 ln (x^{2} + 5)

What is ln(n^2+k^2)-ln(n^2) ?
The solution to ln(n^2+k^2)-ln(n^2) is ln((n^2+k^2)/(n^2))