What is (1.3)^2+ln(1.3)-ln(2e^1) ?

The solution to (1.3)^2+ln(1.3)-ln(2e^1) is 1.69+ln(0.23912…)

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simplify (1.3)^2+ln(1.3)-ln(2e^1)

simplify

(1.3)^{2} + ln (1.3) - ln (2 e^{1})

1.69 + ln (0.23912 \dots)

Decimal Notation

0.25921 \dots

Solution steps

(1.3)^{2} + ln (1.3) - ln (2 e^{1})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (1.3) - ln (2 e^{1}) = ln (\frac{1.3}{2 e ^{1}})

= 1. 3^{2} + ln (\frac{1.3}{2 e ^{1}})

\frac{1.3}{2 e ^{1}} = 0.23912 \dots

= 1. 3^{2} + ln (0.23912 \dots)

1. 3^{2} = 1.69

= 1.69 + ln (0.23912 \dots)

ln (\frac{1}{x c})

\frac{1}{59049} \cdot ln^{- 1} (\frac{1}{3})

- \frac{1}{0.22} ln (\frac{1}{150})

ln (\frac{x + 4}{2})

lo g_{10} (\frac{1}{2 π})

What is (1.3)^2+ln(1.3)-ln(2e^1) ?
The solution to (1.3)^2+ln(1.3)-ln(2e^1) is 1.69+ln(0.23912…)