What is ln((1+e^{-x})/(2-3x)) ?

The solution to ln((1+e^{-x})/(2-3x)) is ln(1+e^{-x})-ln(2-3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln((1+e^{-x})/(2-3x))

simplify

ln (\frac{1 + e ^{- x}}{2 - 3 x})

ln (1 + e^{- x}) - ln (2 - 3 x)

Solution steps

ln (\frac{1 + e ^{- x}}{2 - 3 x})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1 + e ^{- x}}{2 - 3 x}) = ln (1 + e^{- x}) - ln (2 - 3 x)

= ln (e^{- x} + 1) - ln (- 3 x + 2)

ln (\frac{r ^{2} s ^{11}}{t ^{14}})

\frac{1}{5} ln (x + 1) + \frac{4}{5} ln (x - 4)

5 lo g_{7} (y) - \frac{3}{5} lo g_{7} (z)

lo g_{10} (\frac{[ 1.02 ]}{[ 0.875 ]}) + 4.757

3 ln (x) - ln (y)

What is ln((1+e^{-x})/(2-3x)) ?
The solution to ln((1+e^{-x})/(2-3x)) is ln(1+e^{-x})-ln(2-3x)