What is ln(((e^x+e^{-x}))/2) ?

The solution to ln(((e^x+e^{-x}))/2) is ln(e^x+e^{-x})-ln(2)

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simplify ln(((e^x+e^{-x}))/2)

simplify

ln (\frac{( e ^{x} + e ^{- x} )}{2})

ln (e^{x} + e^{- x}) - ln (2)

Solution steps

ln (\frac{( e ^{x} + e ^{- x} )}{2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( e ^{x} + e ^{- x} )}{2}) = ln ((e^{x} + e^{- x})) - ln (2)

= ln (e^{x} + e^{- x}) - ln (2)

ln (\frac{3}{4}) \cdot \frac{3}{4} + ln (\frac{1}{4}) \cdot \frac{1}{4}

0.3 \cdot ln (x) - ln (x + 3)

- lo g_{10} (7.98 \cdot 1 0^{- 2})

ln (e^{x}) + ln (2)

9 \cdot ln (- 1155 \cdot 3)

What is ln(((e^x+e^{-x}))/2) ?
The solution to ln(((e^x+e^{-x}))/2) is ln(e^x+e^{-x})-ln(2)