What are the solutions to the equation 8x^2+64=0 ?

The solutions to the equation 8x^2+64=0 are x=2sqrt(2)i,x=-2sqrt(2)i

Find the zeros of 8x^2+64=0

The zeros of 8x^2+64=0 are x=2sqrt(2)i,x=-2sqrt(2)i

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8 x^{2} + 64 = 0

x = 22 i, x = - 22 i

Solution steps

8 x^{2} + 64 = 0

Move

64

to the right side

8 x^{2} = - 64

Divide both sides by

8

x^{2} = - 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 8, x = - - 8

- 8 = 22 i

- - 8 = - 22 i

x = 22 i, x = - 22 i

2 x^{2} + 2 x \geq x^{2} - 2 x + 5

24 x^{3} - 9 x^{2} y^{2} - 12

1 1^{\frac{1}{3}} \cdot 12 1^{\frac{1}{3}}

(4)^{\frac{3}{2}}

- 5 + 2

What are the solutions to the equation 8x^2+64=0 ?
The solutions to the equation 8x^2+64=0 are x=2sqrt(2)i,x=-2sqrt(2)i
Find the zeros of 8x^2+64=0
The zeros of 8x^2+64=0 are x=2sqrt(2)i,x=-2sqrt(2)i