What is expand log_{2}((s^5)/(7t^2)) ?

The solution to expand log_{2}((s^5)/(7t^2)) is 5log_{2}(s)-log_{2}(7)-2log_{2}(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand log_{2}((s^5)/(7t^2))

expand

lo g_{2} (\frac{s ^{5}}{7 t ^{2}})

5 lo g_{2} (s) - lo g_{2} (7) - 2 lo g_{2} (t)

Solution steps

lo g_{2} (\frac{s ^{5}}{7 t ^{2}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{2} (\frac{s ^{5}}{7 t ^{2}}) = lo g_{2} (s^{5}) - lo g_{2} (7 t^{2})

= lo g_{2} (s^{5}) - lo g_{2} (7 t^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{2} (s^{5}) = 5 lo g_{2} (s)

= 5 lo g_{2} (s) - lo g_{2} (7 t^{2})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{2} (7 t^{2}) = lo g_{2} (7) + lo g_{2} (t^{2})

= 5 lo g_{2} (s) - (lo g_{2} (t^{2}) + lo g_{2} (7))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{2} (t^{2}) = 2 lo g_{2} (t)

= 5 lo g_{2} (s) - (lo g_{2} (7) + 2 lo g_{2} (t))

- (lo g_{2} (7) + 2 lo g_{2} (t)) : - lo g_{2} (7) - 2 lo g_{2} (t)

= 5 lo g_{2} (s) - lo g_{2} (7) - 2 lo g_{2} (t)

ln (\frac{e x + 1}{e x - 1})

lo g_{2} (1.5 \cdot a)

10 ln (\frac{2 \cdot 1 0 ^{- 7}}{1 0 ^{- 12}})

ln (x) + ln (6)

ln (\frac{3}{2}) + 2

What is expand log_{2}((s^5)/(7t^2)) ?
The solution to expand log_{2}((s^5)/(7t^2)) is 5log_{2}(s)-log_{2}(7)-2log_{2}(t)