What is 20log_{10}((0.05)/(4pi*8*10^3))+8+8 ?

The solution to 20log_{10}((0.05)/(4pi*8*10^3))+8+8 is 20log_{10}(0.05)+16-20log_{10}(32000pi)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 20log_{10}((0.05)/(4pi810^3))+8+8

simplify

20 lo g_{10} (\frac{0.05}{4 π \cdot 8 \cdot 1 0 ^{3}}) + 8 + 8

20 lo g_{10} (0.05) + 16 - 20 lo g_{10} (32000 π)

Decimal Notation

- 110.06659 \dots

Solution steps

20 lo g_{10} (\frac{0.05}{4 π 8 \cdot 1 0 ^{3}}) + 8 + 8

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{0.05}{4 π 8 \cdot 1 0 ^{3}}) = lo g_{10} (0.05) - lo g_{10} (4 π 8 \cdot 1 0^{3})

= 20 (lo g_{10} (0.05) - lo g_{10} (1 0^{3} \cdot 4 \cdot 8 π)) + 8 + 8

lo g_{10} (4 π 8 \cdot 1 0^{3}) = lo g_{10} (32000 π)

= 20 (lo g_{10} (0.05) - lo g_{10} (32000 π)) + 8 + 8

Expand

20 (lo g_{10} (0.05) - lo g_{10} (32000 π)) : 20 lo g_{10} (0.05) - 20 lo g_{10} (32000 π)

= 20 lo g_{10} (0.05) - 20 lo g_{10} (32000 π) + 8 + 8

Add the numbers:

8 + 8 = 16

= 20 lo g_{10} (0.05) + 16 - 20 lo g_{10} (32000 π)

5 \cdot lo g_{10} (x) + 7 \cdot lo g_{10} (y)

3 ln (x) + \frac{1}{x} + ln (x + 1) + c

lo g_{10} (\frac{( 4 \cdot 1 0 ^{- 7} )}{( 1 0 ^{- 12} )})

ln (\frac{41}{140})

2 lo g_{10} (6) - 0.5 lo g_{10} (9)

What is 20log_{10}((0.05)/(4pi*8*10^3))+8+8 ?
The solution to 20log_{10}((0.05)/(4pi*8*10^3))+8+8 is 20log_{10}(0.05)+16-20log_{10}(32000pi)