What is log_{10}(60e^{0.032*5}) ?

The solution to log_{10}(60e^{0.032*5}) is log_{10}(60)+0.16log_{10}(e)

Popular >

simplify log_{10}(60e^{0.032*5})

simplify

lo g_{10} (60 e^{0.032 \cdot 5})

lo g_{10} (60) + 0.16 lo g_{10} (e)

Decimal Notation

1.84763 \dots

Solution steps

lo g_{10} (60 e^{0.032 \cdot 5})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (60 e^{0.032 \cdot 5}) = lo g_{10} (60) + lo g_{10} (e^{0.032 \cdot 5})

= lo g_{10} (60) + lo g_{10} (e^{5 \cdot 0.032})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (e^{0.032 \cdot 5}) = 0.032 \cdot 5 lo g_{10} (e)

= lo g_{10} (60) + 0.032 \cdot 5 lo g_{10} (e)

Multiply the numbers:

0.032 \cdot 5 = 0.16

= lo g_{10} (60) + 0.16 lo g_{10} (e)

3 ln (x + 5) - ln (x + 2)

107.22 - 35 + 10 \cdot lo g_{10} (\frac{12}{32})

ln ((2 x e^{y})^{2}) + e^{(y + l n (3 x))}

2 ln (x + 1) - ln (x + 2)

4.41927 + 5 lo g_{10} (\frac{161}{10})

What is log_{10}(60e^{0.032*5}) ?
The solution to log_{10}(60e^{0.032*5}) is log_{10}(60)+0.16log_{10}(e)