What is 6.1+log_{10}((24.5)/(1.01)) ?

The solution to 6.1+log_{10}((24.5)/(1.01)) is 6.1++log_{10}(24.5)-log_{10}(1.01)

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simplify 6.1+log_{10}((24.5)/(1.01))

simplify

6.1 + lo g_{10} (\frac{24.5}{1.01})

6.1 + + lo g_{10} (24.5) - lo g_{10} (1.01)

Decimal

7.48484 \dots

Solution steps

6.1 + lo g_{10} (\frac{24.5}{1.01})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{24.5}{1.01}) = lo g_{10} (24.5) - lo g_{10} (1.01)

= 6.1 + + lo g_{10} (24.5) - lo g_{10} (1.01)

ln (- e^{- x} (1 + \frac{1}{3} e^{- 2 x}))

x - 3 + ln (\frac{x}{( x + 2 )})

ln (7) + ln (8)

ln (\frac{3}{2} a e^{- \frac{3}{2} a x})

ln (2) - 2 ln (6)

What is 6.1+log_{10}((24.5)/(1.01)) ?
The solution to 6.1+log_{10}((24.5)/(1.01)) is 6.1++log_{10}(24.5)-log_{10}(1.01)