What are the solutions to the equation 3x^2+12x=63 ?

The solutions to the equation 3x^2+12x=63 are x=3,x=-7

Find the zeros of 3x^2+12x=63

The zeros of 3x^2+12x=63 are x=3,x=-7

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3 x^{2} + 12 x = 63

x = 3, x = - 7

Solution steps

3 x^{2} + 12 x = 63

Move

63

to the left side

3 x^{2} + 12 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 63 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 63) = 30

x_{1, 2} = \frac{- 12 \pm 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 30}{2 \cdot 3}, x_{2} = \frac{- 12 - 30}{2 \cdot 3}

x = \frac{- 12 + 30}{2 \cdot 3} : 3

x = \frac{- 12 - 30}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

\frac{5 x - 3}{3} + \frac{23 x + 25 x ^{2}}{15} = \frac{1 - 5 x ^{2} + 5 x}{5}

2 x^{2} - 12 x - 182 = 0

(3 x - 5)^{2} - (2 x + 1)^{2} = 24

x, f = a (x - h)^{2} + k

4 n^{2} - 9 = - n

What are the solutions to the equation 3x^2+12x=63 ?
The solutions to the equation 3x^2+12x=63 are x=3,x=-7
Find the zeros of 3x^2+12x=63
The zeros of 3x^2+12x=63 are x=3,x=-7