What are the solutions to the equation x^2-2x=-x+6 ?

The solutions to the equation x^2-2x=-x+6 are x=3,x=-2

Find the zeros of x^2-2x=-x+6

The zeros of x^2-2x=-x+6 are x=3,x=-2

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x^{2} - 2 x = - x + 6

x = 3, x = - 2

Solution steps

x^{2} - 2 x = - x + 6

Move

6

to the left side

x^{2} - 2 x - 6 = - x

Move

x

to the left side

x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

x = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

\frac{( 3 x - 1 ) ^{2}}{16} - (x - \frac{1}{4}) (x + \frac{1}{4}) = - \frac{7}{8}

x^{2} + 6 x + 10 = - x

x, 4 x^{2} + 2 x y + 4 y^{2} = 1

A, (A - 1)^{2} + (B - 2)^{2} = 0

10 m^{2} - 19 = 0

What are the solutions to the equation x^2-2x=-x+6 ?
The solutions to the equation x^2-2x=-x+6 are x=3,x=-2
Find the zeros of x^2-2x=-x+6
The zeros of x^2-2x=-x+6 are x=3,x=-2