What are the solutions to the equation 5x(x+3)=4x(x+2)-x-16 ?

The solutions to the equation 5x(x+3)=4x(x+2)-x-16 are x=-4

Find the zeros of 5x(x+3)=4x(x+2)-x-16

The zeros of 5x(x+3)=4x(x+2)-x-16 are x=-4

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5 x (x + 3) = 4 x (x + 2) - x - 16

x = - 4

Solution steps

5 x (x + 3) = 4 x (x + 2) - x - 16

Expand

5 x (x + 3) : 5 x^{2} + 15 x

Expand

4 x (x + 2) - x - 16 : 4 x^{2} + 7 x - 16

5 x^{2} + 15 x = 4 x^{2} + 7 x - 16

Switch sides

4 x^{2} + 7 x - 16 = 5 x^{2} + 15 x

Move

15 x

to the left side

4 x^{2} - 8 x - 16 = 5 x^{2}

Move

5 x^{2}

to the left side

- x^{2} - 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) ( - 16 )}{2 ( - 1 )}

(- 8)^{2} - 4 (- 1) (- 16) = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 8 )}{2 ( - 1 )}

\frac{- ( - 8 )}{2 ( - 1 )} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

(8 y + 17) (9 y + 27) = 0

x^{2} - 3 x + 9 = 12

x^{2} + 8 x - 24 = 3 x

6 x^{2} + 3 x - 6 = 0

x^{2} + 5 x + 1 = 5 x + 2

What are the solutions to the equation 5x(x+3)=4x(x+2)-x-16 ?
The solutions to the equation 5x(x+3)=4x(x+2)-x-16 are x=-4
Find the zeros of 5x(x+3)=4x(x+2)-x-16
The zeros of 5x(x+3)=4x(x+2)-x-16 are x=-4