What are the solutions to the equation 5e^2+50e=-125 ?

The solutions to the equation 5e^2+50e=-125 are e=-5

Find the zeros of 5e^2+50e=-125

The zeros of 5e^2+50e=-125 are e=-5

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5 e^{2} + 50 e = - 125

e = - 5

Solution steps

5 e^{2} + 50 e = - 125

Move

125

to the left side

5 e^{2} + 50 e + 125 = 0

Solve with the quadratic formula

e_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 5 \cdot 125}{2 \cdot 5}

5 0^{2} - 4 \cdot 5 \cdot 125 = 0

e_{1, 2} = \frac{- 50 \pm 0}{2 \cdot 5}

e = \frac{- 50}{2 \cdot 5}

\frac{- 50}{2 \cdot 5} = - 5

e = - 5

The solution to the quadratic equation is:

e = - 5

x^{2} + 2 x - 9 = 2 x

36.5 = 1.25 v^{2} - 4.375

x^{2} - 10 x + 21 = x - 3

x^{2} + \frac{90}{2000} x + \frac{1500}{2000} = 0

x^{2} + 24 x + 143 = 0

What are the solutions to the equation 5e^2+50e=-125 ?
The solutions to the equation 5e^2+50e=-125 are e=-5
Find the zeros of 5e^2+50e=-125
The zeros of 5e^2+50e=-125 are e=-5